100x^2+260x-162=0

Solution for 100x^2+260x-162=0 equation:

100x^2+260x-162=0

a = 100; b = 260; c = -162;
Δ = b2-4ac
Δ = 2602-4·100·(-162)
Δ = 132400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132400}=\sqrt{400*331}=\sqrt{400}*\sqrt{331}=20\sqrt{331}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(260)-20\sqrt{331}}{2*100}=\frac{-260-20\sqrt{331}}{200}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(260)+20\sqrt{331}}{2*100}=\frac{-260+20\sqrt{331}}{200}
$